What is resting potential? How does the conduction of a nerve impulse take place?

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(N/A) Resting potential is the electrical potential difference across the resting axonal membrane.
Neurons are excitable cells because their membranes are in a polarised state.
Different types of ion channels are present on the neural membrane,which are selectively permeable to different ions.
When a neuron is not conducting any impulse (resting state),the axonal membrane is comparatively more permeable to $K^{+}$ and nearly impermeable to $Na^{+}$.
Similarly,the membrane is impermeable to negatively charged proteins present in the axoplasm.
The axoplasm inside the axon contains a high concentration of $K^{+}$ and negatively charged proteins,and a low concentration of $Na^{+}$.
In contrast,outside the axon,there is a low concentration of $K^{+}$ and a high concentration of $Na^{+}$,forming a concentration gradient.
These ionic gradients across the resting membrane are maintained by the active transport of $3 Na^{+}$ outwards and $2 K^{+}$ inwards by the $Na^{+}-K^{+}$ pump.
As a result,the outer surface of the axonal membrane is positively charged and its inner surface becomes negatively charged; thus,it is polarised.
When a stimulus is applied at point $A$ on the polarised membrane,it becomes freely permeable to $Na^{+}$. The influx of $Na^{+}$ causes a reversal of polarity (depolarisation),where the outer membrane becomes negatively charged and the inner side becomes positively charged.
The electrical potential difference across the plasma membrane at the site $A$ is called the action potential,which is termed a nerve impulse.
At sites immediately ahead (e.g.,site $B$),the axon membrane still has a positive charge on the outer surface and a negative charge on its inner surface.
As a result,a current flows on the inner surface from site $A$ to site $B$,and on the outer surface,current flows from site $B$ to site $A$ to complete the circuit.
Consequently,the polarity at site $B$ is reversed,and an action potential is generated there.
This sequence is repeated along the length of the axon,conducting the impulse.
The stimulus-induced permeability to $Na^{+}$ is short-lived and is quickly followed by a rise in permeability to $K^{+}$. Within a fraction of a second,$K^{+}$ diffuses outside,restoring the resting potential of the membrane.

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When a nerve fiber is stimulated,what does the inner surface of the membrane become?

The nerve fibre in its resting stage is

What happens during depolarization of the nerve membrane?

Define the following terms:
$(1)$ Nerve impulse
$(2)$ Resting potential

$A$: In the nervous system,the generation of an action potential depends upon the influx of sodium ions into the axoplasm.
$R$: The influx of sodium ions during nerve impulse generation is due to the efflux of potassium ions.

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